(0) Obligation:

Clauses:

fold(X, [], Z) :- ','(!, eq(X, Z)).
fold(X, Y, Z) :- ','(head(Y, H), ','(tail(Y, T), ','(myop(X, H, V), fold(V, T, Z)))).
myop(a, b, a).
head([], X1).
head(.(H, X2), H).
tail([], []).
tail(.(X3, T), T).
eq(X, X).

Query: fold(g,g,a)

(1) PrologToDTProblemTransformerProof (SOUND transformation)

Built DT problem from termination graph DT10.

(2) Obligation:

Triples:

foldA(.(b, X1), X2) :- foldA(X1, X2).
foldB(a, .(b, X1), X2) :- foldA(X1, X2).

Clauses:

foldcA([], a).
foldcA(.(b, X1), X2) :- foldcA(X1, X2).

Afs:

foldB(x1, x2, x3)  =  foldB(x1, x2)

(3) TriplesToPiDPProof (SOUND transformation)

We use the technique of [DT09]. With regard to the inferred argument filtering the predicates were used in the following modes:
foldB_in: (b,b,f)
foldA_in: (b,f)
Transforming TRIPLES into the following Term Rewriting System:
Pi DP problem:
The TRS P consists of the following rules:

FOLDB_IN_GGA(a, .(b, X1), X2) → U2_GGA(X1, X2, foldA_in_ga(X1, X2))
FOLDB_IN_GGA(a, .(b, X1), X2) → FOLDA_IN_GA(X1, X2)
FOLDA_IN_GA(.(b, X1), X2) → U1_GA(X1, X2, foldA_in_ga(X1, X2))
FOLDA_IN_GA(.(b, X1), X2) → FOLDA_IN_GA(X1, X2)

R is empty.
The argument filtering Pi contains the following mapping:
a  =  a
.(x1, x2)  =  .(x1, x2)
b  =  b
foldA_in_ga(x1, x2)  =  foldA_in_ga(x1)
FOLDB_IN_GGA(x1, x2, x3)  =  FOLDB_IN_GGA(x1, x2)
U2_GGA(x1, x2, x3)  =  U2_GGA(x1, x3)
FOLDA_IN_GA(x1, x2)  =  FOLDA_IN_GA(x1)
U1_GA(x1, x2, x3)  =  U1_GA(x1, x3)

We have to consider all (P,R,Pi)-chains

Infinitary Constructor Rewriting Termination of PiDP implies Termination of TRIPLES

(4) Obligation:

Pi DP problem:
The TRS P consists of the following rules:

FOLDB_IN_GGA(a, .(b, X1), X2) → U2_GGA(X1, X2, foldA_in_ga(X1, X2))
FOLDB_IN_GGA(a, .(b, X1), X2) → FOLDA_IN_GA(X1, X2)
FOLDA_IN_GA(.(b, X1), X2) → U1_GA(X1, X2, foldA_in_ga(X1, X2))
FOLDA_IN_GA(.(b, X1), X2) → FOLDA_IN_GA(X1, X2)

R is empty.
The argument filtering Pi contains the following mapping:
a  =  a
.(x1, x2)  =  .(x1, x2)
b  =  b
foldA_in_ga(x1, x2)  =  foldA_in_ga(x1)
FOLDB_IN_GGA(x1, x2, x3)  =  FOLDB_IN_GGA(x1, x2)
U2_GGA(x1, x2, x3)  =  U2_GGA(x1, x3)
FOLDA_IN_GA(x1, x2)  =  FOLDA_IN_GA(x1)
U1_GA(x1, x2, x3)  =  U1_GA(x1, x3)

We have to consider all (P,R,Pi)-chains

(5) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 3 less nodes.

(6) Obligation:

Pi DP problem:
The TRS P consists of the following rules:

FOLDA_IN_GA(.(b, X1), X2) → FOLDA_IN_GA(X1, X2)

R is empty.
The argument filtering Pi contains the following mapping:
.(x1, x2)  =  .(x1, x2)
b  =  b
FOLDA_IN_GA(x1, x2)  =  FOLDA_IN_GA(x1)

We have to consider all (P,R,Pi)-chains

(7) PiDPToQDPProof (SOUND transformation)

Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.

(8) Obligation:

Q DP problem:
The TRS P consists of the following rules:

FOLDA_IN_GA(.(b, X1)) → FOLDA_IN_GA(X1)

R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.

(9) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • FOLDA_IN_GA(.(b, X1)) → FOLDA_IN_GA(X1)
    The graph contains the following edges 1 > 1

(10) YES